Wednesday 6th April 2016 PHYSICS PRACTICAL (ALT. A) 9.30AM – 12.15PM +++++++++++++++++++++++++++++++++ We Are Very Sorry For This Delay, We thought Waec Will Change The Question Which We Have Already . We Will Make All Preparations to Deliver Out Answers Before Exam Time . (3a) TABULATE S/N|E(v)|V(v)|I(A)|V^-1(v^-1)|I^-1(A^-1) 1 |1.50|0.80|0.40| 1.250 |2.500 2 |3.00|1.40|0.70| 0.714 |1.429 3 |4.50|2.00|1.00| 0.500 |1.000 4 |6.00|2.50|1.20| 0.400 |0.833 5 |7.50|3.20|1.50| 0.313 |0.667 Precautions: -I tightened all the wires tightly together -I ensured clean terminals -I avoided zero error on the ammeter used (3bi) -By using electric cells -By using electrostatic method (3bii) For parallel connection=1/R=1/R+1/R 2Rt=R Rt=R/2ohm Total=(R/2)+2 4=(R/2)+2 4=(R+4)/2 8=R+4 8-4=R R=4ohm ==================================== (1i) Centre of gravity =50.5 TABULATE S/N|A(cm)| B(cm) 1 |10.0 | 51.90 2 |15.0 | 53.50 3 |20.0 | 53.80 4 |25.0 | 54.90 5 |30.0 | 55.80 1) S/N: 1 , 2 , 3 , 4 , 5 , 6 V(cm): 10.00 , 15.00 , 20.00 , 25.00 , 30.00 , 35.00 U(cm): 47.00 , 48.00 , 50.00 , 51.50 , 53.00 , 54.00 1a) Slope = Change in Y/Change in X = Y2 - Y1 / X2 - X1 = 51.50 - 50.00/25.00 - 20.00 = 1.50/5.00 = 0.30 Ki = (1 - 2S / S)100 = (1 - 2 x 0.30 / 0.3)100 = 1.33 K2 = 2C/S - 160 = 2x44.50/0.3 - 160 = 136.67 1x) * I ensure that I avoides paralax error when taking from the meter rule * I ensure that I avoided drought to prevent swingling of the mass 1bi) The condition under which rigid body remains in equilibrum when acted upon the three non parallel coplanner forces are I) The force must be corrected ie they must meet at point II) The resultant force must be equal to Zero III) The force can be represented in magnitude and direction by sides of a triangular.(1xii) -I avoided the effect of draught during the experiment -I avoided error due to parallax on the metre rule -I balanced the metre rule horizontally on the knife edge before taking my readings (1bi) Moment of a force about a point is the product of the force and its perpendicular distance from the point to the line of action of the force. i.e moment=force*time and its unit is Nm (1bii) -Sum of forces acting in one direction must equal to the forces acting in another direction. -The algebraic sum of moment acting about a point must be equal to zero MORE ANSWERS LOADING......
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