NECO PHYSICS ANSWERS
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Physics OBJ:
1-10: BAEDEECDEB
11-20: CDADDDBCBB
21-30: DBEBBEADEB
31-40: ABEBCBCCDA
41-50: BDBCEDAAAE
51-60: AAABBACECA
Neco Physics ANSWERS By Mr- Fun of Funloaded.com
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1ai)
i)Rockets are used for space travels.
ii)Rockets are used for launching satellites into space
1aii)
i)Artificial Satellites are used to send signals for televisions,radio, etc
ii)Artificial satellites they are used for monitoring cloud patterns for a weather station
1b
A propeller like piece called turbine is been rotated continuously by falling water from a dam, which then turns a metal shaft in an electric generator,which is the motor that produces electricity
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2a)
CLICK HERE TO VIEW NO.2 IMAGE
i)distance covered=5m+10m=15m
ii)magnitude of his displacement
=a^2=b^2+c^2
x^2=5^2+10^2=25+100
x^2=125
x=sqr125
=5sqr5m
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4a)
i)pulley
ii)the inclined plane
4b)
CLICK HERE TO VIEW NO4b IMAGE
load------>fulcrum------>effort
eg-crowbar
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5)
V1=700cm^3, T1=30dgree-census+273=303k, P1=606mmHg
V2=700-300=400cm^3, T2=47+273=320k
from general gas law
P1V1/T1 = P2V2/T2
606*700/303=P2*400/320
P2=606*700*320/303*400
P2=1120mmHg
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8a)
Electric current is the rate of charge flow past a given point in an electric circuit, measured in Coulombs/second which is named Amperes.
8b)
d=30cm,£=1.5*10^-5c r=30cm
30/100=0.3m
V=kE/r=9*10^9*1.5*10^-5/0.3
=13.5*10^4
=13.5*10^5/3
V=4.5*10^5
V=450kv
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9a)
i)by heating
ii)electrical method
9b)
energy stored=1/2CV^2
given that t
C=4HF =4*10^-6F
v=800v
=1/2*4*10^-6*800*800
=2*800*800*10^-6
=1280000j*10^-6
=1.28j
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11)
Tabulate
-Hard Xray-
i)high penetrating power
ii)short wave length
iii)produce high voltage
-soft Xray-
i)low penetrating power
ii)long wave length
iii)produced at low voltage
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12) CLICK HERE TO VIEW NO.12 IMAGE
centre of gravity can be define as the point through which the line of action of the weight of the body always passes irrespective of the position of the body.
12b)
C.g = centre of gravity
:- v= u - gt
Of maximum height v=O - K
O= u-gt
For vertical component, U =uSin tita
Therefore O= usin tita- gt
gt =uSin tita
T=uSin tita/g
Where T is the time taken to maximum height
12c)
Taken moment about point A
Cwm = {60*10)+ (20*60)
Cwm=600+1200
Cwm=1800
Acwm = (20*40) + (R3 * 40)
Acwm=800+80R3
At equilibrium, Cwm=Acwm
1800=800+40r3
1800-800=40r3
1000=40r3
R3=1000/40
R3=25N
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13a)
dew point is the temperature at which the water vapour present in the atmosphere is just sufficent to saturate it
13b)
mist is formed as a result of condensed drops of moisture throughout the mass of cooled air. That is when water droplet in the air cool suddenly
13ci)
the plastic comb will acquire electric charges
13cii)
the plasic com can attract small pieces of paper due to the acquired charges
13di)
area expansivity(B)=2§
=2*1.2*10^-5
B=2.4*10^-5 1k
13dii)
given that initial length=6cm
initial area A=6*6=36cm^2
rise in temperature =25k
linear expansivity=1.2*10^-5/k
area expansivity =2.4*10^-5/k
new area At=Ao(1+Btita)
At=36(1+2.4*10^-5*25)
At=36(1+ 60*10^-5)
At=36(1+0.0006)
At=36(1.0006)
At=36.0216
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15a)
electrical potential is the workdone in driving a unit charge of electric current from one point to another in a closed circuit. It is measured in volta(V)
15b)
CLICK HERE TO VIEW NO.15b IMAGE
A metal rod can be made into a magnet by divided touch me thod as shown in the diagram above.
The metal rod is stroke at the middle with opposite pole end of two permanent magnets towards the opposite ends several times opposite polarity are then formed
15ci)
CLICK HERE TO VIEW NO.15ci IMAGE
VR=120v---->Vl=50v---->Vc=134.39v
220v,506z
15cii)
V^2=Vr^2+(Vl-Vc)^2
220^2=120^2+(50-Vc)^2
48400=14400+(50-Vc)^2
48400=14400=(50-Vc)^2
34000=(50-Vc)^2
50-Vc=sqr34000
50-Vc=184.39
-Vc=184.39-5
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