CORRECTED VERSION
MATHEMATICS OBJ. 1CCAAC 6BADAA 11BCCCB 16BCBBB 21DDBBD 26CCCBA 31ADABC 36CCACD 41ADADA 46CCDBB
BEST OF LUCK
PLS NOTE THIS SYMBOLS
^ means Raise to power
* means multiplication
sqrt or root means Sqr root
/ means division or divide
degree means degree sign that looks like small zero
tita means tita sign that looks like crossed-zero
NOTE: SUBSCRIBERS GOT ANSWERS SINCE 2A.M ALWAYS SUBSCRIBE TO GET ANSWERS EARLY
(1a)
[2whole1/2+1whole3/4/1whole2/5)]/[2whole1/4)-1whole1/2)]
[5/2+7/4/7/5]/[9/4-3/2]
=[5/2+7/4*5/7]/[9/4-3/2]
[5/2+5/4]/[9/4-3/2]
=[(10+5/4)/(9-6/4)]
=(15/4)/(3/4)
=15/4*4/3
=5
(1b)
From tan60/1*PR/3√2
PR=3√2*1/√3
=3√2/√3*√3/√3
=3√6/3=√6
From sin45/1*√6/x
x=√6*√2
=√12
=√4*3
=2√3
==============
2a)
A=p(1+r/100)^n
A=2205000
n=2
r=5%
p=?
2205000=p(1+5/100)^2
2205000=p(1.05)^2
p=2205000/(1.05)^2
p=N2,000,000
(2b)
Area=30cm^2,
h/b=3/2
Area=1/2bh
b=2h/3
30=1/3*2h/3*h
2h^2=30*2*3
h^2=30*2*3/2
h^2=9
h=√9
h=9.49m
====================
(3)
2x/1-2/5y=2y/1(isosceles angle)
LCM = 5
10x-2y=10y
10x=10y+2y
x=12y/10
x=6y/5......(1)
2x-2/55y+2whole1/4c+1/2+2y=180(sum of angle in a triangle)
2x/1-2y/5+(9/4)x+y/2+2y=180
LCM = 20
40x-8y+45x+10y+40y=3600
40x+45x-8y+50y=3600
95x+42y=3600....(2)
Substitute for x in eq...2
95(6y/5)+42y=3600
19(6y)+42y=3600
114y+42y=3600
156y/156=3600/156
y=23.08
Subst for y in equ...1
x=6(23.08)/5
x=27.69
=========================================
(7a)
Log6y+2log6x= 3
Log6y+log6x²= 3
Log6(x²y)= 3
X²y = 6³
X²y = 216
Y= 216/x²
(7b)
(I). Percentage who liked football and volleyball but not boxing = 20
(II)
Percentage who liked exactly two sports = 40 + 20 + 10 = 70
(III)
Summing
5+5+10+40+20+10+5+x = 100%
X + 95 = 100
X = 100– 95 = 5%
Percentage who like none= 5%
============================================
(9a) Diagram
(9b)
a= 360-330 (angle at a point)
=030 degree
b=a=030degree(alternate angles)
Φ = 090degree+030degre
= 120degree
(i) find distance AC wing.
|AC|²= |BC|²+|AB|²–2|AB||BC|Cos tita
|AC|²= 300²+100²–2(300)(100)Cos120degree
= 90000+10000–60000×(-0.5)
=100,000+30,000
= 130,000
|AC| = √130,000 = 360.555KM
=360.56Km(2d.p)
(ii)
find β, applying the first rule
300/Sinβ = 360.56/Sin120
Sinβ = 300sin120/360.56 = 259.81/360.56
= 0.7206
β = sin inverse(0.7206)
= 46degree
Therefore the bearing of the plane from A
=330–046
=284degrees.
11)
A=(2,3,4,5,6,7,8,9,10,11,12)
B=10,11,12,13...24)
M=(4,8,12,16,20,24,28)
(a)
Pr(MnA)=3/7
(b)
Pr(MnB^1)1-PrMnB)
=1-4/7
=3/7
(c)
Pr(Mn(AuB)
AuB=(2,3,4,5...14)
Mn(AuB)=(4,8,12,16,20,24
Pr(Mn(AuB)NOW
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